Sorry, but answer a is not the right answer.
Please try again.
|
Answer b is incorrect.
Please read the question again and make another choice.
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No, c is a wrong answer.
Please repeat this question.
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This answer, d, is incorrect.
Please review this question and try again.
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Answer e is a wrong answer.
Please repeat this question.
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Yes! That's the right answer!
Now move to the next question.
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Right! You chose the correct answer!
Continue with the next question.
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You are right!
Move along to the next question.
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Good choice! That's the right answer!
Now for the next question.
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You picked the correct answer!
Continue to the next question.
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| CHM 115 |
-- |
Interactive Quiz #3 |
-- |
Dr. Robert E. Belford |
This quiz has 10 questions. It is designed to quiz yourself on the
material. You are responsible for reviewing material from questions
answered incorrectly.
DO NOT CLICK THE MOUSE BUTTONS. Simply press
AND HOLD DOWN the mouse button over the
identifying letter (a - e) that you choose as the correct answer.
A message will appear on the screen giving you the result of your
choice.
If you picked a wrong answer, release the mouse button and try
again.
If you picked the right answer the computer will move you to the
next question as soon as you release the mouse button.
If you have any problems with the cursor or with a message that
remains on the screen when you release the mouse button, try
- 1) moving the mouse around
- 2) clicking on the identifying letter you chose.
One of these procedures should clear the screen and let you
proceed.
You can start now with Question #1.
01. Barium Sulfate is formed by the following reaction
Ba(NO3)2(aq) + Na2SO4(aq) --> BaSO4 + 2NaNO3
In an experiment 25.0 g of sodium sulfate is mixed with 25.0 g of barium nitrate and 20.0 g of barium sulfate is produced. What is the theoritical yield?
- a 22.3g
- b 28.0g
- c 233g
- d 261g
- e 142g
02. Barium Sulfate is formed by the following reaction
Ba(NO3)2(aq) + Na2SO4(aq) --> BaSO4 + 2NaNO3
In an experiment 25.0 g of sodium sulfate is mixed with 25.0 g of barium nitrate and 20.0 g of barium sulfate is produced. What is the percent yield?
- a 10.4%
- b 112%
- c 80%
- d 89.6%
- e 20%
03. Calculate the molarity of a solution prepared by diluting 25.0g of sodium sulfate to 250 ml.
- a 10 M
- b 0.704 M
- c 0.0176M
- d 1.42M
- e none of the above
04. Calculate the molarity of a solution prepared by diluting 25.0g of sodium sulfate to 500 ml.
- a 5 M
- b 2.84 M
- c 0.352
- d .704M
- e none of the above
05. What volume of concentrated nitric acid (15.4 M) is required to make 2.5 liters of .5M nitric acid
- a 325 ml
- b 81.2 ml
- c 123 ml
- d 308 ml
- e none of the above
06. What is the chloride concentration when 10.0 g of aluminium chloride is diluted to 100. ml with water?
- a 1.33M
- b 0.250 M
- c 2.25 M
- d 0.750 M
- e none of the above
07. What is the chloride concentration if you dilute 10.0 ml of the solution in problem 6 to 20.0 ml?
- a 1.13M
- b 3.75
- c 0.250
- d 0.375
- e none of the above
08. What vol (in mL) of copper(II)sulfate contains 0.0500 mole of sulfate ions if the solution was made by diluting 20.0 g of copper(II)sulfate to 250 ml with water
- a 99.7 ml
- b 4.98 ml
- c 125 ml
- d 39.9 ml
- e none of the above
= THE END =
You have finished this quiz.